9x^2+14x=8x-1

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Solution for 9x^2+14x=8x-1 equation: 



9x^2+14x=8x-1

We move all terms to the left:

9x^2+14x-(8x-1)=0

We get rid of parentheses

9x^2+14x-8x+1=0

We add all the numbers together, and all the variables

9x^2+6x+1=0

a = 9; b = 6; c = +1;
Δ = b2-4ac
Δ = 62-4·9·1
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-6}{18}=-1/3$

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